n***@gmail.com
2005-12-13 00:48:10 UTC
I couldn't find much on google, so if any of you guys would like to
dirty your hands I would greatly appreciate it. :)
My textbook gives the following info:
2*NH3(g) + CO2(g) --> CO(NH2)2(g) + H20(l)
The reaction is exothermic == 133.5kJ
So, I am supposed to find the enthalpy of formation for urea, I have
the rest of the enthalpys on a chart. So I end up getting:
Delta H(r) = Delta H(f) Products - Delta H(f) reactants
X kJ(CO(NH2)2) + (-285.5kJ)(H2O) - (2*(-46kJ))(2*NH3) - (-393.5kJ)(CO2)
= (-133.5kJ)
X + 200kJ = (-133.5kJ)
X = (-333.5kJ/mol)
Unfortunatly the textbook gives me (-533.5 Kj/mol) our answers differ
by 200kJ meaning my calculation is wrong by 2x... I don't get it.
Anyone have any insight where I am messing up?
dirty your hands I would greatly appreciate it. :)
My textbook gives the following info:
2*NH3(g) + CO2(g) --> CO(NH2)2(g) + H20(l)
The reaction is exothermic == 133.5kJ
So, I am supposed to find the enthalpy of formation for urea, I have
the rest of the enthalpys on a chart. So I end up getting:
Delta H(r) = Delta H(f) Products - Delta H(f) reactants
X kJ(CO(NH2)2) + (-285.5kJ)(H2O) - (2*(-46kJ))(2*NH3) - (-393.5kJ)(CO2)
= (-133.5kJ)
X + 200kJ = (-133.5kJ)
X = (-333.5kJ/mol)
Unfortunatly the textbook gives me (-533.5 Kj/mol) our answers differ
by 200kJ meaning my calculation is wrong by 2x... I don't get it.
Anyone have any insight where I am messing up?